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4x^2-5x-44=0
a = 4; b = -5; c = -44;
Δ = b2-4ac
Δ = -52-4·4·(-44)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-27}{2*4}=\frac{-22}{8} =-2+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+27}{2*4}=\frac{32}{8} =4 $
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